The angle of initial deflection of a particle off the nucleus.
The width of a nucleon = 137 rod widths, therefore, the extra being at the mid of the nucleon, line L = 68.5. Diameter of a rod = 1, so radius = 1/2, so A = ½. Because all tangents to a circle from a common point are the same length, then B = L, & ∆ PON = ∆ PMN. sin a = A / C, sin a = .50 / 68.5018240, sin a = .0072990, therefore angle a = .4181960
∆ PMQ and ∆ ONQ have a common angle, c1 and similar 900 angles (x and x1) therefore angle b1 = a + a1 or .8363920.
Therefore the angle of deflection is .8363920 from the surface of the nucleon, and the angle of deviation from left to right has a maximum of 1.6727840 from each other.
If this occurs in any phenomenon, I do not know, but the two particles probably are not propagated simultaneously so these angles probably do not apply in any direct manner.